What is the integral from 7 to 9 of (x-7)^6 ?

The integral from 7 to 9 of (x-7)^6 is 128/7

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integral from 7 to 9 of (x-7)^6

\int_{7}^{9} (x - 7)^{6} d x

\frac{128}{7}

Decimal Notation

18.28571 \dots

Solution steps

\int_{7}^{9} (x - 7)^{6} d x

Apply u-substitution

: \int_{0}^{2} u^{6} d u

= \int_{0}^{2} u^{6} d u

Apply the Power Rule

: [\frac{u ^{7}}{7}]_{0}^{2}

= [\frac{u ^{7}}{7}]_{0}^{2}

Compute the boundaries:

\frac{128}{7}

= \frac{128}{7}

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What is the integral from 7 to 9 of (x-7)^6 ?
The integral from 7 to 9 of (x-7)^6 is 128/7