What is the derivative of f(x)=(x^4)/3-6x ?

The derivative of f(x)=(x^4)/3-6x is (4x^3)/3-6

What is the first derivative of f(x)=(x^4)/3-6x ?

The first derivative of f(x)=(x^4)/3-6x is (4x^3)/3-6

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derivative of

f (x) = \frac{x ^{4}}{3} - 6 x

\frac{4 x ^{3}}{3} - 6

Solution steps

\frac{d}{d x} (\frac{x ^{4}}{3} - 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{4}}{3}) - \frac{d}{d x} (6 x)

\frac{d}{d x} (\frac{x ^{4}}{3}) = \frac{4 x ^{3}}{3}

\frac{d}{d x} (6 x) = 6

= \frac{4 x ^{3}}{3} - 6

x \to 0 lim (x^{2} + 11)

f (x) = 9 x^{2} + 94, at x = 6

\frac{\partial}{\partial y} (e^{x + y + 3})

\frac{\partial}{\partial x} (\frac{3}{x} - 1 - y)

4 x + 8, x^{2} + 19 x + 62, [- 9, - 6]

What is the derivative of f(x)=(x^4)/3-6x ?
The derivative of f(x)=(x^4)/3-6x is (4x^3)/3-6
What is the first derivative of f(x)=(x^4)/3-6x ?
The first derivative of f(x)=(x^4)/3-6x is (4x^3)/3-6