What is the integral from 1 to infinity of-ln(x) ?

The integral from 1 to infinity of-ln(x) is diverges

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integral from 1 to infinity of-ln(x)

\int_{1}^{\infty} - ln (x) d x

diverges

Solution steps

\int_{1}^{\infty} - ln (x) d x

Compute the indefinite integral:

\int - ln (x) d x = - x ln (x) + x + C

Compute the boundaries:

\int_{1}^{\infty} - ln (x) d x =

diverges

= diverges

\int_{3}^{3.5} 2 d x

\int_{1}^{2} (4 - r^{2}) r d r

\int_{2}^{4} (ln (x))^{3} d x

\int_{0}^{1} \frac{12}{x ^{2} - 9} d x

\int_{0}^{1} 2 - 2 cos (x) d x

What is the integral from 1 to infinity of-ln(x) ?
The integral from 1 to infinity of-ln(x) is diverges