What is the integral from 0 to y/4 of e^{-y^2} ?

The integral from 0 to y/4 of e^{-y^2} is (sqrt(pi))/2 \erf(y/4)

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integral from 0 to y/4 of e^{-y^2}

\int_{0}^{\frac{y}{4}} e^{- y^{2}} d y

\frac{π}{2} erf (\frac{y}{4})

Solution steps

\int_{0}^{\frac{y}{4}} e^{- y^{2}} d y

Use the nonelementary integral:

\int e^{- y^{2}} d y = \frac{π}{2} erf (y)

= [\frac{π}{2} erf (y)]_{0}^{\frac{y}{4}}

Compute the boundaries:

\frac{π}{2} erf (\frac{y}{4})

= \frac{π}{2} erf (\frac{y}{4})

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\int_{2}^{4} x^{2} - 4 x + 3 d x

What is the integral from 0 to y/4 of e^{-y^2} ?
The integral from 0 to y/4 of e^{-y^2} is (sqrt(pi))/2 \erf(y/4)