What is the integral from 0 to 1 of 1/(sqrt(t)) ?

The integral from 0 to 1 of 1/(sqrt(t)) is 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of 1/(sqrt(t))

\int_{0}^{1} \frac{1}{t} d t

2

Solution steps

\int_{0}^{1} \frac{1}{t} d t

Apply the Power Rule

: [2 t^{\frac{1}{2}}]_{0}^{1}

= [2 t^{\frac{1}{2}}]_{0}^{1}

Apply radical rule:

= [2 t]_{0}^{1}

Compute the boundaries:

2

= 2

\int_{0}^{\frac{π}{2}} x cos (8 x) d x

\int_{π}^{2 π} sin (n x) d x

\int_{0}^{5} \frac{x}{25} d x

\int_{11}^{\infty} \frac{1}{x ^{4}} d x

\int_{1}^{2} sec^{3} (θ) d θ

What is the integral from 0 to 1 of 1/(sqrt(t)) ?
The integral from 0 to 1 of 1/(sqrt(t)) is 2