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Popular >

integral from 0 to 2z of-1+x

Solution

\int_{0}^{2 z} - 1 + x d x

Solution

- 2 z + 2 z^{2}

Solution steps

\int_{0}^{2 z} - 1 + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{2 z} 1 d x + \int_{0}^{2 z} x d x

\int_{0}^{2 z} 1 d x = 2 z

\int_{0}^{2 z} x d x = 2 z^{2}

= - 2 z + 2 z^{2}

Popular Examples

integral from 0 to 5 of sqrt(x)sqrt(5-x)

\int_{0}^{5} x 5 - x d x

integral from 1 to 3 of (e^xln(x))

\int_{1}^{3} (e^{x} ln (x)) d x

integral from 0 to pi/6 of tan(2θ)

\int_{0}^{\frac{π}{6}} tan (2 θ) d θ

integral from 1 to 2 of V

\int_{1}^{2} V d V

integral from x^2 to 1 of 4x

\int_{x^{2}}^{1} 4 x d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 2z of-1+x ?
The integral from 0 to 2z of-1+x is -2z+2z^2