What is the integral from x to 0 of cos(u) ?

The integral from x to 0 of cos(u) is -sin(x)

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integral from x to 0 of cos(u)

\int_{x}^{0} cos (u) d u

- sin (x)

Solution steps

\int_{x}^{0} cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= [sin (u)]_{x}^{0}

Compute the boundaries:

- sin (x)

= - sin (x)

\int_{- 0.9}^{- 0.1} \frac{3 e ^{3 x}}{( e ^{3 x} + 3 ) ^{4}} d x

\int_{1}^{2} \frac{3}{7} x^{2} x d x

\int_{2}^{y} t^{2} sin (t) d t

\int_{0}^{2 π} e^{c o s (x)} d x

\int_{4}^{12} 1 + 2 x d x

What is the integral from x to 0 of cos(u) ?
The integral from x to 0 of cos(u) is -sin(x)