What is the limit as x approaches 3 of x/(x^2-9) ?

The limit as x approaches 3 of x/(x^2-9) is diverges

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limit as x approaches 3 of x/(x^2-9)

x \to 3 lim (\frac{x}{x ^{2} - 9})

diverges

Solution steps

x \to 3 lim (\frac{x}{x ^{2} - 9})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{x}{x ^{2} - 9}) = \infty

x \to 3 - lim (\frac{x}{x ^{2} - 9}) = - \infty

= diverges

\frac{\partial}{\partial x} (5 x y - 10 y)

\frac{d}{d x} ((8 x - 2 x^{2}) cos (y))

y = (x^{3} + 8) e^{x}

\int (x^{3} + 4)^{4} (3 x^{2}) d x

\frac{d}{d x} (x x)

What is the limit as x approaches 3 of x/(x^2-9) ?
The limit as x approaches 3 of x/(x^2-9) is diverges