What is the integral from-10pi to 10pi of cos(x) ?

The integral from-10pi to 10pi of cos(x) is 0

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integral from-10pi to 10pi of cos(x)

\int_{- 10 π}^{10 π} cos (x) d x

0

Solution steps

\int_{- 10 π}^{10 π} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= [sin (x)]_{- 10 π}^{10 π}

Compute the boundaries:

0

= 0

\int_{1}^{1} 4 - x^{2} d x

\int_{- 1}^{3} (∣ 2 - x ∣ + x^{2}) d x

\int_{0}^{3} 6 t 1 + t^{2} d t

\int_{- 1}^{1} 2 + x^{2} d x

\int_{1}^{4} - 2 x^{2} + 10 x - 8 d x

What is the integral from-10pi to 10pi of cos(x) ?
The integral from-10pi to 10pi of cos(x) is 0