What is the integral from 1 to t of 1/(sqrt(x)) ?

The integral from 1 to t of 1/(sqrt(x)) is 2sqrt(t)-2

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integral from 1 to t of 1/(sqrt(x))

\int_{1}^{t} \frac{1}{x} d x

2 t - 2

Solution steps

\int_{1}^{t} \frac{1}{x} d x

Apply the Power Rule

: [2 x^{\frac{1}{2}}]_{1}^{t}

= [2 x^{\frac{1}{2}}]_{1}^{t}

Apply radical rule:

= [2 x]_{1}^{t}

Compute the boundaries:

2 t - 2

= 2 t - 2

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What is the integral from 1 to t of 1/(sqrt(x)) ?
The integral from 1 to t of 1/(sqrt(x)) is 2sqrt(t)-2