What is the integral from 0 to 4 of 1/(\sqrt[3]{x)} ?

The integral from 0 to 4 of 1/(\sqrt[3]{x)} is 3\sqrt[3]{2}

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integral from 0 to 4 of 1/(\sqrt[3]{x)}

Decimal Notation

3.77976 \dots

Solution steps

Apply the Power Rule

: [\frac{3}{2} x^{\frac{2}{3}}]_{0}^{4}

= [\frac{3}{2} x^{\frac{2}{3}}]_{0}^{4}

Compute the boundaries:

\int_{2 x + 3}^{x^{3}} e^{- t^{2}} d t

\int_{1}^{2} (2 - \frac{1}{2} x)^{2} d x

\int_{0}^{2} x^{3} 4 x^{2} + 1 d x

\int_{1}^{3.5} \frac{2}{25} (x - 1) d x

\int_{2}^{3} \frac{1}{x - 2} d x

What is the integral from 0 to 4 of 1/(\sqrt[3]{x)} ?
The integral from 0 to 4 of 1/(\sqrt[3]{x)} is 3\sqrt[3]{2}