What is the integral from-8 to 3 of sqrt(1+|x|) ?

The integral from-8 to 3 of sqrt(1+|x|) is 22

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integral from-8 to 3 of sqrt(1+|x|)

\int_{- 8}^{3} 1 + ∣ x ∣ d x

22

Solution steps

\int_{- 8}^{3} 1 + ∣ x ∣ d x

Eliminate Absolutes

= \int_{- 8}^{0} 1 - x d x + \int_{0}^{3} 1 + x d x

\int_{- 8}^{0} 1 - x d x = \frac{52}{3}

\int_{0}^{3} 1 + x d x = \frac{14}{3}

= \frac{52}{3} + \frac{14}{3}

Simplify

\frac{52}{3} + \frac{14}{3} : 22

= 22

\int_{- 2}^{1} (x^{2} + 1)^{2} d x

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\int_{0}^{8} 2 x + 3 d x

\int_{- 2}^{2} \frac{x}{1 - x} d x

What is the integral from-8 to 3 of sqrt(1+|x|) ?
The integral from-8 to 3 of sqrt(1+|x|) is 22