What is the integral from 0 to infinity of 1/θ ?

The integral from 0 to infinity of 1/θ is diverges

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integral from 0 to infinity of 1/θ

\int_{0}^{\infty} \frac{1}{θ} d θ

diverges

Solution steps

\int_{0}^{\infty} \frac{1}{θ} d θ

Compute the indefinite integral:

\int \frac{1}{θ} d θ = ln ∣ θ ∣ + C

Compute the boundaries:

\int_{0}^{\infty} \frac{1}{θ} d θ =

diverges

= diverges

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\int_{0}^{1} \frac{6 x}{3 x ^{2} + 1} d x

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\int_{0}^{2} \frac{1}{20} d x

What is the integral from 0 to infinity of 1/θ ?
The integral from 0 to infinity of 1/θ is diverges