What is the integral from-1 to 1 of mx^2 ?

The integral from-1 to 1 of mx^2 is (2m)/3

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integral from-1 to 1 of mx^2

\int_{- 1}^{1} m x^{2} d x

\frac{2 m}{3}

Solution steps

\int_{- 1}^{1} m x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= m \cdot \int_{- 1}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 1}^{1}

= m [\frac{x ^{3}}{3}]_{- 1}^{1}

Compute the boundaries:

\frac{2}{3}

= m \frac{2}{3}

Simplify

= \frac{2 m}{3}

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What is the integral from-1 to 1 of mx^2 ?
The integral from-1 to 1 of mx^2 is (2m)/3