What is the integral from 0 to 1 of x^3+(x^4)/2 ?

The integral from 0 to 1 of x^3+(x^4)/2 is 7/20

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integral from 0 to 1 of x^3+(x^4)/2

\int_{0}^{1} x^{3} + \frac{x ^{4}}{2} d x

\frac{7}{20}

Decimal Notation

0.35

Solution steps

\int_{0}^{1} x^{3} + \frac{x ^{4}}{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{3} d x + \int_{0}^{1} \frac{x ^{4}}{2} d x

\int_{0}^{1} x^{3} d x = \frac{1}{4}

\int_{0}^{1} \frac{x ^{4}}{2} d x = \frac{1}{10}

= \frac{1}{4} + \frac{1}{10}

Simplify

\frac{1}{4} + \frac{1}{10} : \frac{7}{20}

= \frac{7}{20}

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What is the integral from 0 to 1 of x^3+(x^4)/2 ?
The integral from 0 to 1 of x^3+(x^4)/2 is 7/20