What is (\partial)/(\partial z)(4x^3+z^2) ?

The answer to (\partial)/(\partial z)(4x^3+z^2) is 2z

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(\partial)/(\partial z)(4x^3+z^2)

\frac{\partial}{\partial z} (4 x^{3} + z^{2})

2 z

Solution steps

\frac{\partial}{\partial z} (4 x^{3} + z^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (4 x^{3}) + \frac{\partial}{\partial z} (z^{2})

\frac{\partial}{\partial z} (4 x^{3}) = 0

\frac{\partial}{\partial z} (z^{2}) = 2 z

= 0 + 2 z

Simplify

= 2 z

7 x^{4}

x, x, x = 0, x = 2

\frac{\partial}{\partial x} (cos^{2} (x))

\int (sin (x))^{3} (cos (x))^{2} d x

\frac{d}{d x} (ln (324 sin^{2} (x)))

What is (\partial)/(\partial z)(4x^3+z^2) ?
The answer to (\partial)/(\partial z)(4x^3+z^2) is 2z