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Popular >

integral from-2 to 1 of (2x^2+2)

Solution

\int_{- 2}^{1} (2 x^{2} + 2) d x

Solution

12

Solution steps

\int_{- 2}^{1} 2 x^{2} + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{1} 2 x^{2} d x + \int_{- 2}^{1} 2 d x

\int_{- 2}^{1} 2 x^{2} d x = 6

\int_{- 2}^{1} 2 d x = 6

= 6 + 6

Simplify

= 12

Popular Examples

integral from 0 to 1.25 of x^3+2x^2-3

\int_{0}^{1.25} x^{3} + 2 x^{2} - 3 d x

integral from 0 to y^3 of e^{y^4}

\int_{0}^{y^{3}} e^{y^{4}} d y

integral from 0 to pi/2 of sin^2(2t)

\int_{0}^{\frac{π}{2}} sin^{2} (2 t) d t

integral from 0 to 11 of x

\int_{0}^{11} x d x

integral from-8 to 27 of 1/(x^{1/3)}

\int_{- 8}^{27} \frac{1}{x ^{\frac{1}{3}}} d x

Frequently Asked Questions (FAQ)

What is the integral from-2 to 1 of (2x^2+2) ?
The integral from-2 to 1 of (2x^2+2) is 12