What is the integral from 0 to pi of 2+cos(x) ?

The integral from 0 to pi of 2+cos(x) is 2pi

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integral from 0 to pi of 2+cos(x)

\int_{0}^{π} 2 + cos (x) d x

2 π

Decimal Notation

6.28318 \dots

Solution steps

\int_{0}^{π} 2 + cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} 2 d x + \int_{0}^{π} cos (x) d x

\int_{0}^{π} 2 d x = 2 π

\int_{0}^{π} cos (x) d x = 0

= 2 π + 0

Simplify

= 2 π

\int_{0}^{10} 2 x - 3 d x

\int_{0}^{\frac{π}{4}} e^{- x} sin (x) d x

\int_{0}^{3} (x 1 + x) d x

\int_{0}^{r} b \cdot r^{3} + c \cdot r^{2} d r

\int_{0}^{2 π} x^{3} d x

What is the integral from 0 to pi of 2+cos(x) ?
The integral from 0 to pi of 2+cos(x) is 2pi