What is the integral from 1 to 3x^2 of (sin(t))/t ?

The integral from 1 to 3x^2 of (sin(t))/t is \Si(3x^2)-0.9460830704

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integral from 1 to 3x^2 of (sin(t))/t

\int_{1}^{3 x^{2}} \frac{sin ( t )}{t} d t

Si (3 x^{2}) - 0.9460830704

Solution steps

\int_{1}^{3 x^{2}} \frac{sin ( t )}{t} d t

Use the nonelementary integral:

\int \frac{sin ( x )}{x} d x = Si (x)

= [Si (t)]_{1}^{3 x^{2}}

Compute the boundaries:

Si (3 x^{2}) - 0.9460830704

= Si (3 x^{2}) - 0.9460830704

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What is the integral from 1 to 3x^2 of (sin(t))/t ?
The integral from 1 to 3x^2 of (sin(t))/t is \Si(3x^2)-0.9460830704