What is the integral from x^2 to 4x-3 of 1 ?

The integral from x^2 to 4x-3 of 1 is 4x-3-x^2

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integral from x^2 to 4x-3 of 1

\int_{x^{2}}^{4 x - 3} 1 d y

4 x - 3 - x^{2}

Solution steps

\int_{x^{2}}^{4 x - 3} 1 d y

Integral of a constant:

\int a d x = a x

= [1 \cdot y]_{x^{2}}^{4 x - 3}

Simplify

= [y]_{x^{2}}^{4 x - 3}

Compute the boundaries:

4 x - 3 - x^{2}

= 4 x - 3 - x^{2}

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What is the integral from x^2 to 4x-3 of 1 ?
The integral from x^2 to 4x-3 of 1 is 4x-3-x^2