What is the integral of 4/(3x+2) ?

The integral of 4/(3x+2) is 4/3 ln|3x+2|+C

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integral of 4/(3x+2)

\int \frac{4}{3 x + 2} d x

\frac{4}{3} ln ∣ 3 x + 2 ∣ + C

Solution steps

\int \frac{4}{3 x + 2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int \frac{1}{3 x + 2} d x

Apply u-substitution

: \int \frac{1}{3 u} d u

= 4 \cdot \int \frac{1}{3 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \frac{1}{3} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 4 \cdot \frac{1}{3} ln ∣ u ∣

Substitute back

u = 3 x + 2

= 4 \cdot \frac{1}{3} ln ∣ 3 x + 2 ∣

Simplify

4 \cdot \frac{1}{3} ln ∣ 3 x + 2 ∣ : \frac{4}{3} ln ∣ 3 x + 2 ∣

= \frac{4}{3} ln ∣ 3 x + 2 ∣

Add a constant to the solution

= \frac{4}{3} ln ∣ 3 x + 2 ∣ + C

x \to 2 lim (4 x - 4.2)

\frac{d ^{3}}{d x ^{3}} (x^{4} - 2 x^{3})

y^{^{'}} = x^{2} + x y

\frac{1}{( s + 1 ) ( s + 1 )}