What is the integral from-2 to-1 of (x^{-4}) ?

The integral from-2 to-1 of (x^{-4}) is 7/24

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integral from-2 to-1 of (x^{-4})

\int_{- 2}^{- 1} (x^{- 4}) d x

\frac{7}{24}

Decimal Notation

0.29166 \dots

Solution steps

\int_{- 2}^{- 1} x^{- 4} d x

Apply the Power Rule

: [- \frac{1}{3 x ^{3}}]_{- 2}^{- 1}

= [- \frac{1}{3 x ^{3}}]_{- 2}^{- 1}

Compute the boundaries:

\frac{7}{24}

= \frac{7}{24}

\int_{- 1}^{2} (3 x^{2} - 5 x)^{3} d x

\int_{0.75}^{1} 2 x d x

\int_{- 2}^{1} (2 x^{2} + 4) d x

\int_{0}^{4} x^{2} - 4 x + 9 d x

\int_{1}^{x^{2}} \frac{1}{1 + ln ( t )} d t

What is the integral from-2 to-1 of (x^{-4}) ?
The integral from-2 to-1 of (x^{-4}) is 7/24