What is the integral from 0 to 2 of x\sqrt[3]{4x} ?

The integral from 0 to 2 of x\sqrt[3]{4x} is 24/7

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integral from 0 to 2 of x\sqrt[3]{4x}

\frac{24}{7}

Decimal Notation

3.42857 \dots

Solution steps

Apply Integration By Parts

\int \frac{4 ^{\frac{1}{3}}}{6} x^{\frac{4}{3}} d x = \frac{4 ^{\frac{1}{3}}}{14} x^{\frac{7}{3}}

Apply radical rule:

Compute the boundaries:

\frac{24}{7}

= \frac{24}{7}

\int_{1}^{10} x - 1 d x

\int_{\frac{π}{6}}^{\frac{π}{3}} cot^{4} (x) d x

\int_{- 64}^{8} \frac{1}{x ^{\frac{1}{3}}} d x

\int_{2}^{5} 5 x^{2} + 13 x - 6 d x

\int_{- 2}^{1} \frac{1}{( x + 1 ) ^{3}} d x

What is the integral from 0 to 2 of x\sqrt[3]{4x} ?
The integral from 0 to 2 of x\sqrt[3]{4x} is 24/7