What is the integral from-1 to-2 of f(t) ?

The integral from-1 to-2 of f(t) is (3t)/2

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integral from-1 to-2 of f(t)

\int_{- 1}^{- 2} f (t)

\frac{3 t}{2}

Solution steps

\int_{- 1}^{- 2} f t df

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{- 2}^{- 1} t fdf

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - t \cdot \int_{- 2}^{- 1} fdf

Apply the Power Rule

: [\frac{f ^{2}}{2}]_{- 2}^{- 1}

= - t [\frac{f ^{2}}{2}]_{- 2}^{- 1}

Compute the boundaries:

- \frac{3}{2}

= - t (- \frac{3}{2})

Simplify

= \frac{3 t}{2}

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What is the integral from-1 to-2 of f(t) ?
The integral from-1 to-2 of f(t) is (3t)/2