What is the integral from 4 to 7 of (x^2+x+2) ?

The integral from 4 to 7 of (x^2+x+2) is 231/2

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integral from 4 to 7 of (x^2+x+2)

\int_{4}^{7} (x^{2} + x + 2) d x

\frac{231}{2}

Decimal Notation

115.5

Solution steps

\int_{4}^{7} x^{2} + x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{4}^{7} x^{2} d x + \int_{4}^{7} x d x + \int_{4}^{7} 2 d x

\int_{4}^{7} x^{2} d x = 93

\int_{4}^{7} x d x = \frac{33}{2}

\int_{4}^{7} 2 d x = 6

= 93 + \frac{33}{2} + 6

Simplify

93 + \frac{33}{2} + 6 : \frac{231}{2}

= \frac{231}{2}

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What is the integral from 4 to 7 of (x^2+x+2) ?
The integral from 4 to 7 of (x^2+x+2) is 231/2