What is the integral from-4pi to-(7pi)/2 of sec(x) ?

The integral from-4pi to-(7pi)/2 of sec(x) is diverges

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integral from-4pi to-(7pi)/2 of sec(x)

\int_{- 4 π}^{- \frac{7 π}{2}} sec (x) d x

diverges

Solution steps

\int_{- 4 π}^{- \frac{7 π}{2}} sec (x) d x

Use the common integral:

\int sec (x) d x = ln ∣ tan (x) + sec (x) ∣

= [ln ∣ tan (x) + sec (x) ∣]_{- 4 π}^{- \frac{7 π}{2}}

Compute the boundaries:

diverges

= diverges

\int_{1}^{5} 5 x^{2} - \frac{x}{3} d x

\int_{2}^{5} \frac{1}{x - 7} d x

\int_{1}^{4} (4 x^{3} - 3 x^{2} + 1) d x

\int_{1}^{3} (\frac{ln ^{2} ( 5 )}{2 x}) d x

\int_{0}^{1} 2 + x^{3} d x

What is the integral from-4pi to-(7pi)/2 of sec(x) ?
The integral from-4pi to-(7pi)/2 of sec(x) is diverges