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Popular >

integral from 0 to 2 of (x/2+1)

Solution

\int_{0}^{2} (\frac{x}{2} + 1) d x

Solution

3

Solution steps

\int_{0}^{2} \frac{x}{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} \frac{x}{2} d x + \int_{0}^{2} 1 d x

\int_{0}^{2} \frac{x}{2} d x = 1

\int_{0}^{2} 1 d x = 2

= 1 + 2

Simplify

= 3

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\int_{0}^{\frac{π}{2}} 7 sin (t) - 2 cos (t) d t

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\int_{2}^{3} \frac{x ^{3} + 2}{x ^{4}} d x

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\int_{0}^{100} 1

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\int_{1}^{e^{6}} x^{4} ln (x) d x

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\int_{0}^{1.2} x d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of (x/2+1) ?
The integral from 0 to 2 of (x/2+1) is 3