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Popular >

integral from-2 to 0 of x^2-4

Solution

\int_{- 2}^{0} x^{2} - 4 d x

Solution

- \frac{16}{3}

+1

Decimal Notation

- 5.33333 \dots

Solution steps

\int_{- 2}^{0} x^{2} - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{0} x^{2} d x - \int_{- 2}^{0} 4 d x

\int_{- 2}^{0} x^{2} d x = \frac{8}{3}

\int_{- 2}^{0} 4 d x = 8

= \frac{8}{3} - 8

Simplify

\frac{8}{3} - 8 : - \frac{16}{3}

= - \frac{16}{3}

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\int_{- 1}^{1} 2 x e^{- inπ x} d x

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\int_{1}^{2} x^{4} ln (3 x) d x

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\int_{- 3}^{- 1} 2 x + 6 d x

integral from x to infinity of e^{-y^2}

\int_{x}^{\infty} e^{- y^{2}} d y

Frequently Asked Questions (FAQ)

What is the integral from-2 to 0 of x^2-4 ?
The integral from-2 to 0 of x^2-4 is -16/3