What is the integral from 0 to 1 of e^{r^2} ?

The integral from 0 to 1 of e^{r^2} is (sqrt(pi))/2 \erfi(1)

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integral from 0 to 1 of e^{r^2}

\int_{0}^{1} e^{r^{2}} d r

\frac{π}{2} erfi (1)

Solution steps

\int_{0}^{1} e^{r^{2}} d r

Use the nonelementary integral:

\int e^{r^{2}} d r = \frac{π}{2} erfi (r)

= [\frac{π}{2} erfi (r)]_{0}^{1}

Compute the boundaries:

\frac{π}{2} erfi (1)

= \frac{π}{2} erfi (1)

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What is the integral from 0 to 1 of e^{r^2} ?
The integral from 0 to 1 of e^{r^2} is (sqrt(pi))/2 \erfi(1)