What is the integral from 0 to 1 of (5x) ?

The integral from 0 to 1 of (5x) is 5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of (5x)

\int_{0}^{1} (5 x) d x

\frac{5}{2}

Decimal Notation

2.5

Solution steps

\int_{0}^{1} 5 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int_{0}^{1} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{1}

= 5 [\frac{x ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= 5 \cdot \frac{1}{2}

Simplify

= \frac{5}{2}

\int_{- π}^{0} - 1

\int_{1}^{2} (- x + 2) d x

\int_{0}^{\frac{π}{2}} e^{2 x} sin (x) d x

\int_{0}^{b} b sin (\frac{π x}{b}) d x

\int_{0}^{1} (arccos (x))^{3} d x

What is the integral from 0 to 1 of (5x) ?
The integral from 0 to 1 of (5x) is 5/2