What is the integral from-infinity to 0 of e^{2t} ?

The integral from-infinity to 0 of e^{2t} is 1/2

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integral from-infinity to 0 of e^{2t}

\int_{- \infty}^{0} e^{2 t} d t

\frac{1}{2}

Decimal Notation

0.5

Solution steps

\int_{- \infty}^{0} e^{2 t} d t

Compute the indefinite integral:

\int e^{2 t} d t = \frac{1}{2} e^{2 t} + C

Compute the boundaries:

\int_{- \infty}^{0} e^{2 t} d t = \frac{1}{2} - 0

= \frac{1}{2} - 0

Simplify

= \frac{1}{2}

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What is the integral from-infinity to 0 of e^{2t} ?
The integral from-infinity to 0 of e^{2t} is 1/2