What is the solution for (12+x^2)y^'-2xy=0 ?

The solution for (12+x^2)y^'-2xy=0 is y=12e^{c_{1}}+e^{c_{1}}x^2

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(12+x^2)y^'-2xy=0

(12 + x^{2}) y^{^{'}} - 2 x y = 0

y = 12 e^{c_{1}} + e^{c_{1}} x^{2}

Solution steps

(12 + x^{2}) y^{'} (x) - 2 x y = 0

Solve separable ODE:

y = 12 e^{c_{1}} + e^{c_{1}} x^{2}

y = 12 e^{c_{1}} + e^{c_{1}} x^{2}

x \to 0 + lim (x^{x})

\frac{\partial}{\partial x} (x^{6} - 8 x^{3} y)

\int λ e^{- λ t} d t

n = 0 \sum \infty (\frac{1}{3})^{n - 1}

\frac{\partial}{\partial x} (9 e^{x} x)

What is the solution for (12+x^2)y^'-2xy=0 ?
The solution for (12+x^2)y^'-2xy=0 is y=12e^{c_{1}}+e^{c_{1}}x^2