What is the integral from 1 to 9 of 3x^2+xsqrt(x)+1 ?

The integral from 1 to 9 of 3x^2+xsqrt(x)+1 is 4164/5

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integral from 1 to 9 of 3x^2+xsqrt(x)+1

\int_{1}^{9} 3 x^{2} + x x + 1 d x

\frac{4164}{5}

Decimal Notation

832.8

Solution steps

\int_{1}^{9} 3 x^{2} + x x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{9} 3 x^{2} d x + \int_{1}^{9} x x d x + \int_{1}^{9} 1 d x

\int_{1}^{9} 3 x^{2} d x = 728

\int_{1}^{9} x x d x = \frac{484}{5}

\int_{1}^{9} 1 d x = 8

= 728 + \frac{484}{5} + 8

Simplify

728 + \frac{484}{5} + 8 : \frac{4164}{5}

= \frac{4164}{5}

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What is the integral from 1 to 9 of 3x^2+xsqrt(x)+1 ?
The integral from 1 to 9 of 3x^2+xsqrt(x)+1 is 4164/5