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Popular >

integral from 1 to 4 of-2x+6

Solution

\int_{1}^{4} - 2 x + 6 d x

Solution

3

Solution steps

\int_{1}^{4} - 2 x + 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{1}^{4} 2 x d x + \int_{1}^{4} 6 d x

\int_{1}^{4} 2 x d x = 15

\int_{1}^{4} 6 d x = 18

= - 15 + 18

Simplify

= 3

Popular Examples

integral from-1 to 2 of 1/(x^2-4x+13)

\int_{- 1}^{2} \frac{1}{x ^{2} - 4 x + 13} d x

integral from 1 to 2 of-x^3+3x^2-2x

\int_{1}^{2} - x^{3} + 3 x^{2} - 2 x d x

integral from 1 to 2 of pi(4-1/2 x)^2

\int_{1}^{2} π (4 - \frac{1}{2} x)^{2} d x

integral from 0 to 1 of x^3+xe^{-x}

\int_{0}^{1} x^{3} + x e^{- x} d x

integral from 0 to infinity of 4e^{-t}

\int_{0}^{\infty} 4 e^{- t} d t

Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of-2x+6 ?
The integral from 1 to 4 of-2x+6 is 3