What is the integral from 1 to 5 of cos(x) ?

The integral from 1 to 5 of cos(x) is sin(5)-sin(1)

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integral from 1 to 5 of cos(x)

\int_{1}^{5} cos (x) d x

sin (5) - sin (1)

Decimal

- 1.80039 \dots

Solution steps

\int_{1}^{5} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= [sin (x)]_{1}^{5}

Compute the boundaries:

sin (5) - sin (1)

= sin (5) - sin (1)

\int_{1}^{9} (\frac{2}{x}) d x

\int_{π}^{x} cos (2 x) d x

\int_{0}^{\frac{π}{4}} x^{2} cos (x) d x

\int_{z}^{2 - z^{2}} z d z

\int_{0}^{t} 5 d t

What is the integral from 1 to 5 of cos(x) ?
The integral from 1 to 5 of cos(x) is sin(5)-sin(1)