intégrale de 1 a 2 de (x^3-3x^2+2x)

Solution

\int_{1}^{2} (x^{3} - 3 x^{2} + 2 x) d x

- \frac{1}{4}

Notation décimale

- 0.25

étapes des solutions

\int_{1}^{2} x^{3} - 3 x^{2} + 2 x d x

Appliquer la règle de la somme:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{3} d x - \int_{1}^{2} 3 x^{2} d x + \int_{1}^{2} 2 x d x

\int_{1}^{2} x^{3} d x = \frac{15}{4}

\int_{1}^{2} 3 x^{2} d x = 7

\int_{1}^{2} 2 x d x = 3

= \frac{15}{4} - 7 + 3

Simplifier

\frac{15}{4} - 7 + 3 : - \frac{1}{4}

= - \frac{1}{4}

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