What is the integral from 16 to 20 of 0.005(20-x) ?

The integral from 16 to 20 of 0.005(20-x) is 0.04

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integral from 16 to 20 of 0.005(20-x)

\int_{16}^{20} 0.005 (20 - x) d x

0.04

Solution steps

\int_{16}^{20} 0.005 (20 - x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.005 \cdot \int_{16}^{20} 20 - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 0.005 (\int_{16}^{20} 20 d x - \int_{16}^{20} x d x)

\int_{16}^{20} 20 d x = 80

\int_{16}^{20} x d x = 72

= 0.005 (80 - 72)

Simplify

= 0.04

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What is the integral from 16 to 20 of 0.005(20-x) ?
The integral from 16 to 20 of 0.005(20-x) is 0.04