What is the integral from 0 to x of cos(x)sin(x) ?

The integral from 0 to x of cos(x)sin(x) is 1/2 sin^2(x)

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integral from 0 to x of cos(x)sin(x)

\int_{0}^{x} cos (x) sin (x) d x

\frac{1}{2} sin^{2} (x)

Solution steps

\int_{0}^{x} cos (x) sin (x) d x

Apply u-substitution

: \int_{0}^{s i n (x)} u d u

= \int_{0}^{s i n (x)} u d u

Apply the Power Rule

: [\frac{u ^{2}}{2}]_{0}^{s i n (x)}

= [\frac{u ^{2}}{2}]_{0}^{s i n (x)}

Compute the boundaries:

\frac{1}{2} sin^{2} (x)

= \frac{1}{2} sin^{2} (x)

\int_{0}^{2} (x^{2} + 8 x) d x

\int_{0}^{s} 1 d s

\int_{0}^{l n (14)} tanh (x) d x

\int_{- 1}^{3} 5 x^{2} - 4 d x

\int_{0}^{1} \frac{5 ^{x}}{5 ^{x} + 1} d x

What is the integral from 0 to x of cos(x)sin(x) ?
The integral from 0 to x of cos(x)sin(x) is 1/2 sin^2(x)