What is the limit as x approaches-infinity of e^xx^2 ?

The limit as x approaches-infinity of e^xx^2 is 0

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limit as x approaches-infinity of e^xx^2

x \to - \infty lim (e^{x} x^{2})

0

Solution steps

x \to - \infty lim (e^{x} x^{2})

Rewrite for L'Hopital

= x \to - \infty lim (\frac{x ^{2}}{\frac{1}{e ^{x}}})

Apply L'Hopital's Rule

: x \to - \infty lim (\frac{2 x}{- e ^{- x}})

= x \to - \infty lim (\frac{2 x}{- e ^{- x}})

Apply L'Hopital's Rule

: x \to - \infty lim (\frac{2}{e ^{- x}})

= x \to - \infty lim (\frac{2}{e ^{- x}})

Simplify

\frac{2}{e ^{- x}} : 2 e^{x}

= x \to - \infty lim (2 e^{x})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 2 \cdot x \to - \infty lim (e^{x})

Apply the common limit:

x \to - \infty lim (e^{x}) = 0

= 2 \cdot 0

Simplify

= 0

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What is the limit as x approaches-infinity of e^xx^2 ?
The limit as x approaches-infinity of e^xx^2 is 0