What is the integral from 3 to 5 of (sin(x-4))/(x-4) ?

The integral from 3 to 5 of (sin(x-4))/(x-4) is -\Si(-1)+0.9460830704

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integral from 3 to 5 of (sin(x-4))/(x-4)

\int_{3}^{5} \frac{sin ( x - 4 )}{x - 4} d x

- Si (- 1) + 0.9460830704

Solution steps

\int_{3}^{5} \frac{sin ( x - 4 )}{x - 4} d x

Find undefined (singularity) points:

x = 4

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{3}^{4} \frac{sin ( x - 4 )}{x - 4} d x + \int_{4}^{5} \frac{sin ( x - 4 )}{x - 4} d x

\int_{3}^{4} \frac{sin ( x - 4 )}{x - 4} d x = - Si (- 1)

\int_{4}^{5} \frac{sin ( x - 4 )}{x - 4} d x = 0.9460830704

= - Si (- 1) + 0.9460830704

\int_{0}^{1} \frac{x y ^{2}}{x ^{2} + 1} d x

\int_{1}^{3} \frac{1}{x ^{2} + 4 x} d x

\int_{1}^{7} (- \frac{1}{3} x^{2} + 3 x) d x

\int_{0}^{\infty} e^{u} d u

\int_{3}^{10} 9 u^{2} - 25 d u

What is the integral from 3 to 5 of (sin(x-4))/(x-4) ?
The integral from 3 to 5 of (sin(x-4))/(x-4) is -\Si(-1)+0.9460830704