What is the integral from 4 to 6 of 1/(sqrt(x-4)) ?

The integral from 4 to 6 of 1/(sqrt(x-4)) is 2sqrt(2)

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integral from 4 to 6 of 1/(sqrt(x-4))

\int_{4}^{6} \frac{1}{x - 4} d x

22

Decimal Notation

2.82842 \dots

Solution steps

\int_{4}^{6} \frac{1}{x - 4} d x

Apply u-substitution

: \int_{0}^{2} 2 d u

= \int_{0}^{2} 2 d u

Integral of a constant:

\int a d x = a x

= [2 u]_{0}^{2}

Compute the boundaries:

22

= 22

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What is the integral from 4 to 6 of 1/(sqrt(x-4)) ?
The integral from 4 to 6 of 1/(sqrt(x-4)) is 2sqrt(2)