What is the integral from-3 to-1 of-3(x^2)/5+x/5+6 ?

The integral from-3 to-1 of-3(x^2)/5+x/5+6 is 6

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integral from-3 to-1 of-3(x^2)/5+x/5+6

\int_{- 3}^{- 1} - 3 \frac{x ^{2}}{5} + \frac{x}{5} + 6 d x

6

Solution steps

\int_{- 3}^{- 1} - 3 \cdot \frac{x ^{2}}{5} + \frac{x}{5} + 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 3}^{- 1} 3 \cdot \frac{x ^{2}}{5} d x + \int_{- 3}^{- 1} \frac{x}{5} d x + \int_{- 3}^{- 1} 6 d x

\int_{- 3}^{- 1} 3 \cdot \frac{x ^{2}}{5} d x = \frac{26}{5}

\int_{- 3}^{- 1} \frac{x}{5} d x = - \frac{4}{5}

\int_{- 3}^{- 1} 6 d x = 12

= - \frac{26}{5} - \frac{4}{5} + 12

Simplify

- \frac{26}{5} - \frac{4}{5} + 12 : 6

= 6

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What is the integral from-3 to-1 of-3(x^2)/5+x/5+6 ?
The integral from-3 to-1 of-3(x^2)/5+x/5+6 is 6