What is the integral from 0 to 1 of (x^{1/2}) ?

The integral from 0 to 1 of (x^{1/2}) is 2/3

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integral from 0 to 1 of (x^{1/2})

\int_{0}^{1} (x^{\frac{1}{2}}) d x

\frac{2}{3}

Decimal Notation

0.66666 \dots

Solution steps

\int_{0}^{1} x^{\frac{1}{2}} d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{1}

= [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{1}

Compute the boundaries:

\frac{2}{3}

= \frac{2}{3}

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What is the integral from 0 to 1 of (x^{1/2}) ?
The integral from 0 to 1 of (x^{1/2}) is 2/3