What is the integral from 0 to x of sec^2(t) ?

The integral from 0 to x of sec^2(t) is tan(x)

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integral from 0 to x of sec^2(t)

\int_{0}^{x} sec^{2} (t) d t

tan (x)

Solution steps

\int_{0}^{x} sec^{2} (t) d t

Use the common integral:

\int sec^{2} (t) d t = tan (t)

= [tan (t)]_{0}^{x}

Compute the boundaries:

tan (x)

= tan (x)

\int_{0}^{1} 2 x - x^{3} d x

\int_{0}^{1} e^{x} 1 + e^{x} d x

\int_{0}^{1} x^{2} 4 x + 7 d x

\int_{0}^{2} 38 z^{2} ln (z) d z

\int_{\frac{π}{4}}^{\frac{π}{2}} (csc^{2} (x)) d x

What is the integral from 0 to x of sec^2(t) ?
The integral from 0 to x of sec^2(t) is tan(x)