What is the integral from-5 to 0 of (3+|x+4|) ?

The integral from-5 to 0 of (3+|x+4|) is 47/2

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integral from-5 to 0 of (3+|x+4|)

\int_{- 5}^{0} (3 + ∣ x + 4 ∣) d x

\frac{47}{2}

Decimal Notation

23.5

Solution steps

\int_{- 5}^{0} 3 + ∣ x + 4 ∣ d x

Eliminate Absolutes

= \int_{- 5}^{- 4} 3 - x - 4 d x + \int_{- 4}^{0} 3 + x + 4 d x

\int_{- 5}^{- 4} 3 - x - 4 d x = \frac{7}{2}

\int_{- 4}^{0} 3 + x + 4 d x = 20

= \frac{7}{2} + 20

Simplify

\frac{7}{2} + 20 : \frac{47}{2}

= \frac{47}{2}

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What is the integral from-5 to 0 of (3+|x+4|) ?
The integral from-5 to 0 of (3+|x+4|) is 47/2