What is the integral from-infinity to 0 of e^{16x} ?

The integral from-infinity to 0 of e^{16x} is 1/16

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integral from-infinity to 0 of e^{16x}

\int_{- \infty}^{0} e^{16 x} d x

\frac{1}{16}

Decimal Notation

0.0625

Solution steps

\int_{- \infty}^{0} e^{16 x} d x

Compute the indefinite integral:

\int e^{16 x} d x = \frac{1}{16} e^{16 x} + C

Compute the boundaries:

\int_{- \infty}^{0} e^{16 x} d x = \frac{1}{16} - 0

= \frac{1}{16} - 0

Simplify

= \frac{1}{16}

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What is the integral from-infinity to 0 of e^{16x} ?
The integral from-infinity to 0 of e^{16x} is 1/16