What is the integral from-1 to 2 of 1/3 x^3 ?

The integral from-1 to 2 of 1/3 x^3 is 5/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 2 of 1/3 x^3

\int_{- 1}^{2} \frac{1}{3} x^{3} d x

\frac{5}{4}

Decimal Notation

1.25

Solution steps

\int_{- 1}^{2} \frac{1}{3} x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int_{- 1}^{2} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{- 1}^{2}

= \frac{1}{3} [\frac{x ^{4}}{4}]_{- 1}^{2}

Compute the boundaries:

\frac{15}{4}

= \frac{1}{3} \cdot \frac{15}{4}

Simplify

= \frac{5}{4}

\int_{0}^{3} k x^{2} + \frac{1}{30} d x

\int_{\frac{y}{2}}^{\frac{1}{2}} e^{- x^{2}} d x

\int_{0}^{π} cos^{7} (x) d x

\int_{0}^{4} 3 x e^{4 x} d x

\int_{0.3}^{1.2} e^{- 0. 3^{2}} d x

What is the integral from-1 to 2 of 1/3 x^3 ?
The integral from-1 to 2 of 1/3 x^3 is 5/4