What is the integral from 0 to 12 of 1/(1+x^2) ?

The integral from 0 to 12 of 1/(1+x^2) is arctan(12)

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integral from 0 to 12 of 1/(1+x^2)

\int_{0}^{12} \frac{1}{1 + x ^{2}} d x

arctan (12)

Decimal Notation

1.48765 \dots

Solution steps

\int_{0}^{12} \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= [arctan (x)]_{0}^{12}

Compute the boundaries:

arctan (12)

= arctan (12)

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What is the integral from 0 to 12 of 1/(1+x^2) ?
The integral from 0 to 12 of 1/(1+x^2) is arctan(12)