What is area 2x^2+4x-2,0,2 ?

The answer to area 2x^2+4x-2,0,2 is 12sqrt(2)+(44-20sqrt(2))/3-12

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area 2x^2+4x-2,0,2

area

2 x^{2} + 4 x - 2, 0, 2

122 + \frac{44 - 20 2}{3} - 12

Decimal Notation

10.20913 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} 2 x^{2} + 4 x - 2 d x

Solve

\int_{0}^{2} 2 x^{2} + 4 x - 2 d x : 122 + \frac{44 - 20 2}{3} - 12

The area is:

= 122 + \frac{44 - 20 2}{3} - 12

81 - x^{2}

\frac{\partial}{\partial y} (x e^{- x - y} sin (y))

\frac{\partial}{\partial y} (x y^{2} e^{y})

f (x) = (5 x^{3} + 2)^{4}

\frac{d}{d x} (tan (arcsin (x)))

What is area 2x^2+4x-2,0,2 ?
The answer to area 2x^2+4x-2,0,2 is 12sqrt(2)+(44-20sqrt(2))/3-12