What is the integral from 0 to 8 of 1/(x^{2/3)} ?

The integral from 0 to 8 of 1/(x^{2/3)} is 6

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integral from 0 to 8 of 1/(x^{2/3)}

\int_{0}^{8} \frac{1}{x ^{\frac{2}{3}}} d x

6

Solution steps

\int_{0}^{8} \frac{1}{x ^{\frac{2}{3}}} d x

Apply the Power Rule

: [3 x^{\frac{1}{3}}]_{0}^{8}

= [3 x^{\frac{1}{3}}]_{0}^{8}

Compute the boundaries:

6

= 6

\int_{0}^{a} \frac{1}{( a - x ) ^{2}} d x

\int_{0}^{6} \frac{280}{x + 2} - 35 d x

\int_{0}^{1} 8 x e^{9 x} d x

\int_{0}^{π} 7 cos (θ) d θ

\int_{0}^{3} r 9 - r^{2} d r

What is the integral from 0 to 8 of 1/(x^{2/3)} ?
The integral from 0 to 8 of 1/(x^{2/3)} is 6